document.write( "Question 850527: This speed up a freight train is 15 mph slower then the speed of a passenger train. The freight train travels 350 Miles in the same time that it takes the passenger train to travel 450 miles. Find the speed of each train. \n" ); document.write( "

Algebra.Com's Answer #512232 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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This speed up a freight train is 15 mph slower then the speed of a passenger train. The freight train travels 350 Miles in the same time that it takes the passenger train to travel 450 miles. Find the speed of each train.
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\n" ); document.write( "Let s = the speed of the freight
\n" ); document.write( "then
\n" ); document.write( "(s+15) = speed of the pass
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( " $\"450%2F%28s%2B15%29\"$ = $\"350%2Fs\"$
\n" ); document.write( "Cross multiply
\n" ); document.write( "450s = 350(s+15)
\n" ); document.write( "450s = 350s + 5250
\n" ); document.write( "450s - 350s = 5250
\n" ); document.write( "s = 5250/100
\n" ); document.write( "s = 52.5 mph is the speed of the freight
\n" ); document.write( "then
\n" ); document.write( "52.5 + 15 = 67.5 mph is the speed of pass train \n" ); document.write( "

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