document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=850157>Question 850157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Alana is making fruit pies for a bake sale. <BR>\n" );
document.write( "The recipe require 3/4 pounds of fruit per pie Alana brought 4 1/2 times the amount of fruit required by the recipe.<BR>\n" );
document.write( " How many pounds of fruit did Alana buy? <BR>\n" );
document.write( "When she finished preparing the pies Alana found that she had used 2/3 of the fruit she had brought. How many pounds of fruit did she have left? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #512180 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=512180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4.5*(.75*p)=b\r<BR>\n" );
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document.write( "b/3=r remaining<BR>\n" );
document.write( "p = pies made<BR>\n" );
document.write( "b= fruit bought<BR>\n" );
document.write( "r = left over fruit<BR>\n" );
document.write( "Not enough info.<BR>\n" );
document.write( "We don't know how many pies she made.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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