document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=850460>Question 850460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How can you solve these two equations by substitution? <BR>\n" );
document.write( "x - 2y = -10<BR>\n" );
document.write( "y = -2x - 6  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #512150 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=512150\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x - 2y = -10 or x=2y-10<BR>\n" );
document.write( "y = -2x - 6  substitute (2y-10) for x in this equation & solve for y.<BR>\n" );
document.write( "y=-2(2y-10)-6<BR>\n" );
document.write( "y=-4y+20-6<BR>\n" );
document.write( "y+4y=14<BR>\n" );
document.write( "5y=14<BR>\n" );
document.write( "y=14/5 ans.<BR>\n" );
document.write( "x=2(14/5)-10<BR>\n" );
document.write( "x=28/5-10<BR>\n" );
document.write( "x=28/5-50/5<BR>\n" );
document.write( "x=-22/5 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "14/5=-2(-22/5)-6<BR>\n" );
document.write( "14/5=44/5-30/5<BR>\n" );
document.write( "14/5=14/5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );