document.write( "Question 850451: Its been a while since I have done functions, so I'm a little confused on this one.
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document.write( "if f(x)=4x/1-x and g(x)=2/x then f(g(x))=\r
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document.write( "the answer is supposed to be 8/x-2 but i got 8/1-x\r
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document.write( "I'm also a bit confused on this one as well
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document.write( "sqrt(a)/1+sqrt(a)= \r
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document.write( "the answer is supposed to be sqrt(a)-a/1-a but I just got 1 \n" );
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Algebra.Com's Answer #512147 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! 1)if f(x)=4x/1-x and g(x)=2/x then \n" ); document.write( "f(g(x))= f(2/x) = 4*(2/x) / (1 - 2/x) \n" ); document.write( "= (8/x) / ((x-2) / x) \n" ); document.write( "= (8/x) * x / (x-2) \n" ); document.write( "= 8 / (x - 2) \n" ); document.write( "2) sqrt(a)/1+sqrt(a)= a^(1/2) / (1 + a^(1/2)) \n" ); document.write( "now multiply the denominator and numerator by (1 - a^(1/2)) and we get \n" ); document.write( "= (a^(1/2) * (1-a^(1/2)) / (1 + a^(1/2)) * (1 - a^(1/2)) \n" ); document.write( "= (a^(1/2) - a) / (1 - a) \n" ); document.write( " \n" ); document.write( " |