document.write( "Question 850419: The area of a square in square feet is represented by 4z^2-36z+81. Find an expression for the perimeter of the square. Then find the perimeter when z=10 feet.\r
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Algebra.Com's Answer #512121 by Seutip(231)\"\" \"About 
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Since this is the area \"4z%5E2-36z%2B81\" and finding for the area of square is
\n" ); document.write( "\"A+=+s%5E2\" where s is the side, the perimeter P=4s.\r
\n" ); document.write( "\n" ); document.write( "In the area \"4z%5E2-36z%2B81\", we can factor it to\r
\n" ); document.write( "\n" ); document.write( "\"4z%5E2-36z%2B81+=+%282z-9%29%282z-9%29\"\r
\n" ); document.write( "\n" ); document.write( "Therefore \"4z%5E2-36z%2B81+=+%282z-9%29%5E2\" ans s = 2z-9\r
\n" ); document.write( "\n" ); document.write( "And the perimeter\r
\n" ); document.write( "\n" ); document.write( "P= 4(2z-9)\r
\n" ); document.write( "\n" ); document.write( "If z=10, substitute\r
\n" ); document.write( "\n" ); document.write( "P = 4(2(10)-9)
\n" ); document.write( "P = 4(20-9)
\n" ); document.write( "P = 4(11)
\n" ); document.write( "P = 44 feet :)\r
\n" ); document.write( "\n" ); document.write( "Hope that helps.\r
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