document.write( "Question 850106: the perimeter of a rectangle is 26cm.The area of the rectangle remains unaltered if the lenght is decreased by 3cm and width is increased by 2cm.Find the dimension of the original rectangle \n" ); document.write( "
Algebra.Com's Answer #512069 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
the perimeter of a rectangle is 26cm. The area of the rectangle remains unaltered if the lenght is decreased by 3cm and width is increased by 2cm.
\n" ); document.write( "Find the dimension of the original rectangle
\n" ); document.write( ":
\n" ); document.write( "2L + 2W = 26
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "L + W = 13
\n" ); document.write( "L = (13-W); use this form for substitution
\n" ); document.write( "Area = LW
\n" ); document.write( "and
\n" ); document.write( "New area = old area
\n" ); document.write( "(L-3)*(W+2) = LW
\n" ); document.write( "Foil
\n" ); document.write( "LW + 2L - 3W - 6 = LW
\n" ); document.write( "Subtract LW from both sides
\n" ); document.write( "2L - 3W + 6 = 0
\n" ); document.write( "Replace L with (13-W)
\n" ); document.write( "2(13-W) - 3w - 6 = 0
\n" ); document.write( "26 - 2W - 3W - 6 = 0
\n" ); document.write( "-5W + 20 = 0
\n" ); document.write( "-5W = -20
\n" ); document.write( "W = -20/-5
\n" ); document.write( "W = 4 cm is the original Width
\n" ); document.write( "then
\n" ); document.write( "13 - 4 = 9 cm is the length
\n" ); document.write( ":
\n" ); document.write( "You can check the area of each, ensure they are equal
\n" ); document.write( " \n" ); document.write( "
\n" );