document.write( "Question 850210: The length of a rectangle is 5 centimeters longer than its width. The area is 24 square centimeters. Find the dimensions of the rectangle. I've tried the formula A=1/2bh but I'm not sure how to find the base and height to plug in. \n" ); document.write( "
Algebra.Com's Answer #512046 by Ash14(5)\"\" \"About 
You can put this solution on YOUR website!
the area ; A =WL
\n" ); document.write( "w=width
\n" ); document.write( "L=length
\n" ); document.write( "........
\n" ); document.write( "now
\n" ); document.write( "\" rectangle is 5 centimeters longer than its width.\"means;
\n" ); document.write( "length=5+W
\n" ); document.write( "..........
\n" ); document.write( "The area is 24 ,MEANS;
\n" ); document.write( "W*L=24
\n" ); document.write( "........
\n" ); document.write( "now we have 2 equations
\n" ); document.write( "the first one is length=5+W
\n" ); document.write( "and the second one is W*L=24
\n" ); document.write( "sub the value of length in second equation
\n" ); document.write( "w*L=24
\n" ); document.write( "W*(5+w)=24
\n" ); document.write( "w*5+W*W=24
\n" ); document.write( "5w+w^2=24
\n" ); document.write( "by simple algebra find value of w
\n" ); document.write( "w^2+5w-24=0
\n" ); document.write( "(w+8)(w-3)=0
\n" ); document.write( "so
\n" ); document.write( "w=3 or w=-8
\n" ); document.write( "we cross out w=-8 (because we can not have a negative value for length)
\n" ); document.write( "so we only use w=3 cm
\n" ); document.write( "...................
\n" ); document.write( "now
\n" ); document.write( "sub value of w in the firs equation
\n" ); document.write( "which is
\n" ); document.write( "length =5+w
\n" ); document.write( "length=5+(3)
\n" ); document.write( "length=8 cm
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\n" ); document.write( "good luck :)\r
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