document.write( "Question 850192: A wall of perimeter 38 m surrounds a rectangular yard of length 12 m. What is the width of the yard? \n" ); document.write( "
Algebra.Com's Answer #512044 by checkley79(3341)\"\" \"About 
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P=2L+2W
\n" ); document.write( "38=2*12+2W
\n" ); document.write( "38=24+2W
\n" ); document.write( "2W=38-24
\n" ); document.write( "2W=14
\n" ); document.write( "W=14/2
\n" ); document.write( "W=7 M. ANS. FOR THE WIDTH
\n" ); document.write( "PROOF:
\n" ); document.write( "38=2*12+2*7
\n" ); document.write( "38=24+14
\n" ); document.write( "38=38
\n" ); document.write( "
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