document.write( "Question 850192: A wall of perimeter 38 m surrounds a rectangular yard of length 12 m. What is the width of the yard? \n" ); document.write( "
Algebra.Com's Answer #512044 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "38=2*12+2W \n" ); document.write( "38=24+2W \n" ); document.write( "2W=38-24 \n" ); document.write( "2W=14 \n" ); document.write( "W=14/2 \n" ); document.write( "W=7 M. ANS. FOR THE WIDTH \n" ); document.write( "PROOF: \n" ); document.write( "38=2*12+2*7 \n" ); document.write( "38=24+14 \n" ); document.write( "38=38 \n" ); document.write( " |