document.write( "Question 849405: how many permutations can be obtained by letter COURAGE if:
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document.write( "(a)constants occupy the even places,
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document.write( "(b)A and E occupy the ends,
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document.write( "(c)C and E come together? \n" );
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Algebra.Com's Answer #512025 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "COURAGE has 3 consonants and 4 vowels \n" ); document.write( "how many permutations can be obtained by letter COURAGE if:\r \n" ); document.write( "\n" ); document.write( "(a)constants occupy the even places, V C V C V C V\r\n" ); document.write( "\r\n" ); document.write( "Choose the 2nd letter as a consonant 3 ways.\r\n" ); document.write( "Choose the 4th letter as a consonant 2 ways.\r\n" ); document.write( "Choose the 2nd letter as a consonant 1 way.\r\n" ); document.write( "Choose the 1st letter as a vowel 4 ways.\r\n" ); document.write( "Choose the 3rd letter as a vowel 3 ways.\r\n" ); document.write( "Choose the 5th letter as a vowel 2 ways.\r\n" ); document.write( "Choose the 7th letter as a vowel 1 way.\r\n" ); document.write( "\r\n" ); document.write( "Answer 3×2×1×4×3×2×1 = 3!4! = 6×24 = 146 ways(b)A and E occupy the ends, 5! ways for A _ _ _ _ _ E and 5! for E _ _ _ _ _ A\r\n" ); document.write( "\r\n" ); document.write( "Answer: 2×5! = 2×120 = 240 ways(c)C and E come together? That's the number of permutations of the 6 things {CE,O,U,R,A,G)\r\n" ); document.write( "plus the number of permutations of the 6 things {EC,O,U,R,A,G)\r\n" ); document.write( "\r\n" ); document.write( "That's 2×6! = 2×720 = 1440 ways.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |