document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1474>Question 1474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 60 inches.  The second side is 10 inches longer than the first side. The third side is 6 inches more than twice the first side. what is the length of the smallest side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #512 by </B><A HREF=/tutors/aboutme.mpl?userid=usyim88hk><B>usyim88hk(158)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=usyim88hk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the length of the first side:<BR>\n" );
document.write( "x = first side<BR>\n" );
document.write( "x+10 = second side<BR>\n" );
document.write( "2x+6 = third side<BR>\n" );
document.write( "Now set up an equation:<BR>\n" );
document.write( "x+x+10+2x+6 = 60 (because three sides add up to 60)<BR>\n" );
document.write( "4x + 16 = 60<BR>\n" );
document.write( "4x = 44<BR>\n" );
document.write( "x = 11<BR>\n" );
document.write( "So the length of the first side is 11<BR>\n" );
document.write( "the length of the second side is 21<BR>\n" );
document.write( "the length of the third side is 28 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );