document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=850118>Question 850118</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "A principal of $7500 is invested in an account paying an annual rate of 7%. Find the amount in the account after 3 years if the account is compounded semiannually, quarterly and monthly.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511980 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(1+I)^T<BR>\n" );
document.write( "7500(1+.07/2)^3*2<BR>\n" );
document.write( "7500(1.035)^6<BR>\n" );
document.write( "7500*1.229=$9,219.41 ANS FOR SEMIANNUAL INTEREST.<BR>\n" );
document.write( "7500(1+.07/4)^3*4<BR>\n" );
document.write( "7500(1.0175)^12<BR>\n" );
document.write( "7500*1.2314=$9,235.79 ANS FOR QUARTERLY INTEREST.<BR>\n" );
document.write( "7500(1+.07/12)^3*12<BR>\n" );
document.write( "7500(1+.005833)^36<BR>\n" );
document.write( "7500*1.2329=$9,246.83 ANS FOR MONTHLY INTEREST.\r<BR>\n" );
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