document.write( "Question 850137: Was wondering if someone could give me the probability and the equation to solve the following.\r
\n" ); document.write( "\n" ); document.write( "Two teams are to play four games against each other. In each game Team A is 45% to win and team B is 55% to win. What it the probability of Team A winning 2 or more of the games (i.e. 2,3 or 4)? Also if you can show me how to figure it out that would be great.\r
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Algebra.Com's Answer #511975 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Note: The probability of x successes in n trials is: 
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document.write( "P (x)=  (p)^x(q)^(n-x) where p and q are the probabilities of success and failure respectively. 
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document.write( "In this case p(A wins) = .45 & q(A loses)  = .55    n = 4
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document.write( " P(x= 2) = (.45)^2(.55)^2
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document.write( " P(x= 3) = (.45)^3(.55)^1
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document.write( " P(x= 4) = (.45)^4(.55)^0   
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document.write( "P(x ≥ 2)= P(x= 2) +  P(x= 3) +  P(x= 4)
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document.write( "0r using TI Calculator
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document.write( "p = .05,  n = 100
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document.write( "P(x ≥ 2) = 1 – P(x ≤ 1) = 1 -  binomcdf(4, .45, 1)\r
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