document.write( "Question 850071: a manufacturer packages bolts in boxes containing 100 each. Each box of 100 bolts contains, on average, 5 defective bolts. the quality control staff randomly selects a box at the end of the day from an entire production run. \r
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\n" ); document.write( "\n" ); document.write( "c. what is the probability, rounded to four decimal places that the box will contain less than 4 defective bolts?
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Algebra.Com's Answer #511970 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "p = .05,  n = 100
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document.write( "using TI Calculator
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document.write( "P(x=3) = The syntax is binompdf(n, p, x-value)= binompdf(100, .05,3)
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document.write( "Or
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document.write( " P = (.05)^3(.95)^100  
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document.write( "Note: The probability of x successes in n trials is: 
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document.write( "P (x)=  (p)^x(q)^(n-x) where p and q are the probabilities of success and failure respectively. 
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document.write( "In this case p = .05 & q  = .95
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document.write( " =  
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document.write( " = 
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document.write( "B. What is the probability, rounded to four decimal places that the box will contain at most 7 defective bolts? 
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document.write( "find P(x ≤ 7)= binomcdf(n, p, largest x-value) = binomcdf(100, .05, 7).
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document.write( " c. what is the probability, rounded to four decimal places that the box will contain less than 4 defective bolts?
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document.write( "find P(x < 4)= binomcdf(n, p, largest x-value) = binomcdf(100, .05, 3). \n" );
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