document.write( "Question 849991: a and b are quadrant 1 angles with cos(a)=15/17 and csc(b)=41/9 find sin (a+b).\r
\n" ); document.write( "\n" ); document.write( "answer options are a. 185/697 b. 455/697 c. 528/697 d. 672/697\r
\n" ); document.write( "\n" ); document.write( "I receive the demonator of 697 but can not find the numerator
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Algebra.Com's Answer #511945 by AnlytcPhil(1810)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "We have to graph the two first quadrant angles, A and B.\r\n" );
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document.write( "Let's draw A first:\r\n" );
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document.write( "We are given this\r\n" );
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document.write( "\"cos%28A%29=15%2F17\" \r\n" );
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document.write( "We know that \"COSINE=ADJACENT%2FHYPOTENUSE\" or \"COSINE=x%2Fr\"\r\n" );
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document.write( "So we make the adjacent side, x, of A in the right triangle equal to the \r\n" );
document.write( "numerator of \"15%2F17\", which is 15.  We make the hypotenuse, r,\r\n" );
document.write( "of the right triangle equal to the denominator of the fraction,\r\n" );
document.write( "which is 17. But we don't yet know y, so we put \"y=? at first.\r\n" );
document.write( "Like this:\r\n" );
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document.write( "Next we find y by the Pythagorean theorem\r\n" );
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document.write( " r² = x²+y²\r\n" );
document.write( "17² = 15²+y²\r\n" );
document.write( "289 = 225+y²\r\n" );
document.write( " 64 = y²\r\n" );
document.write( "  8 = y \r\n" );
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document.write( "So we can erase the question mark and put 8 in its place\r\n" );
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document.write( "Now let's draw to other first quadrant angle B :\r\n" );
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document.write( "We are given this\r\n" );
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document.write( "\"csc%28B%29=41%2F9\" \r\n" );
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document.write( "We know that \"COSECANT=HYPOTENUSE%2FOPPOSITE\" or \"COSECANT=r%2Fy\"\r\n" );
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document.write( "So we make the hypotenuse of the right triangle r, equal to the \r\n" );
document.write( "numerator of \"41%2F9\", which is 41.  We make the opposite side\r\n" );
document.write( "of the right triangle equal to the denominator of the fraction,\r\n" );
document.write( "which is 9. But we don't yet know x, so we put \"x=? at first.\r\n" );
document.write( "Like this:\r\n" );
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document.write( " \r\n" );
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document.write( "Next we find x by the Pythagorean theorem\r\n" );
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document.write( "  r² = x²+y²\r\n" );
document.write( " 41² = x²+9²\r\n" );
document.write( "1681 = x²+81\r\n" );
document.write( "1600 = x²\r\n" );
document.write( "  40 = x\r\n" );
document.write( "  \r\n" );
document.write( "So we can erase the question mark and put 40 in its place:\r\n" );
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document.write( "Now that we have x = adjacent, y = opposite, and r = hypotenuse for\r\n" );
document.write( "both angles A and B, now we can proceed to find sin(A+B)  \r\n" );
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document.write( "Let's put both graphs here for convenience:\r\n" );
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document.write( "  \r\n" );
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document.write( "The identity for sin(A+B) is\r\n" );
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document.write( "sin(A+B) = sin(A)cos(B)+cos(A)sin(B)\r\n" );
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document.write( "sin(A) = \"OPPOSITE%2FHYPOTENUSE\" = \"y%2Fr\" = \"8%2F17\"\r\n" );
document.write( "cos(A) = \"ADJACENT%2FHYPOTENUSE\" = \"x%2Fr\" = \"15%2F17\"\r\n" );
document.write( "sin(B) = \"OPPOSITE%2FHYPOTENUSE\" = \"y%2Fr\" = \"9%2F41\"\r\n" );
document.write( "cos(A) = \"ADJACENT%2FHYPOTENUSE\" = \"x%2Fr\" = \"40%2F41\"\r\n" );
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document.write( "Plug in:\r\n" );
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document.write( "sin(A+B) = sin(A)cos(B)+cos(A)sin(B)\r\n" );
document.write( "sin(A+B) = \"%288%2F17%29%2840%2F41%29%2B%2815%2F17%29%289%2F41%29\" = \"320%2F697%2B135%2F697\" = \"455%2F697\"\r\n" );
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document.write( "Edwin
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