document.write( "Question 850009: If the second side of a right triangle measures 2 more than twice the first, the third side measures 3 times the first, and the perimeter is 38, what is the measurement of the first side of the triangle? \r
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Algebra.Com's Answer #511943 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Sides are these:
\n" ); document.write( "x
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\n" ); document.write( "\"y=2%2B2x\";
\n" ); document.write( "\"z=3x\";
\n" ); document.write( "\"x%2B2%2B2x%2B3x=38\".\r
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\n" ); document.write( "\n" ); document.write( "The perimeter equation is ready for solving for x, the requested \"first side\" of the triangle.
\n" ); document.write( "\"6x%2B2=38\"
\n" ); document.write( "\"6x=36\"
\n" ); document.write( "\"highlight%28x=6%29\"\r
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\n" ); document.write( "\n" ); document.write( "IS THIS A RIGHT TRIANGLE AS DESCRIBED?
\n" ); document.write( "x=6; y=2+2*6=14; z=3*6=18.
\n" ); document.write( "Test in Pythagorean Theorem:
\n" ); document.write( "\"6%5E2%2B14%5E2=18%5E2\"
\n" ); document.write( "\"36%2B196=324\"
\n" ); document.write( "\"232=324\" FALSE!!!!
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\n" ); document.write( "This cannot be a right triangle. A triangle, yes; but NOT a right triangle.
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