document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71574>Question 71574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times the smallest of three consecutive odd integers is nineteen more than twice the largest.  Find the integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51191 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51191\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Three times the smallest of three consecutive odd integers is nineteen more than twice the largest. Find the integers.<BR>\n" );
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document.write( "Consecutive odd integers: 2x+1, 2x+3, 2x+5<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "3(2x+1) = 2(2x+5)+19<BR>\n" );
document.write( "6x+3 = 4x + 29<BR>\n" );
document.write( "2x=26<BR>\n" );
document.write( "2x+1= 27(smallest)<BR>\n" );
document.write( "2x+3 = 29 (2nd smallest)<BR>\n" );
document.write( "2x+5 = 31 (largest)<BR>\n" );
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