document.write( "Question 71575: How many liters of a 40% alcohol solution should be added to 40 liters of a 10% alcohol solution to obtain a 20% alcohol solution. \n" ); document.write( "
Algebra.Com's Answer #51190 by galactus(183)\"\" \"About 
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These mixture problems are the bane of many a student.\r
\n" ); document.write( "\n" ); document.write( "Let x = the amount of 40%\r
\n" ); document.write( "\n" ); document.write( "\"0.40x%2B0.10%2840%29=0.20%28x%2B40%29\"\r
\n" ); document.write( "\n" ); document.write( "You're adding x amount of 40% to the existing 40 liters to get a 20% mix.\r
\n" ); document.write( "\n" ); document.write( "Therefore, we have 0.20(x+40).\r
\n" ); document.write( "\n" ); document.write( "Now, to solve:\r
\n" ); document.write( "\n" ); document.write( "\"0.40x%2B4=0.20x%2B8\"\r
\n" ); document.write( "\n" ); document.write( "\"0.20x=4\"\r
\n" ); document.write( "\n" ); document.write( "\"x=20\" liters of 40% solution added to 40 liters of 10% will give 60 liters of 20%.
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