document.write( "Question 850015: GOOD DAY COULD YOU PLEASE HELP ME: A father is twice the age of his son. In 10 years time the father would have been 52 years old, how old would his son be by then? \n" ); document.write( "
Algebra.Com's Answer #511894 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 52-10=42 =f \n" ); document.write( "s=f/2=42/2=21 \n" ); document.write( "s+10=31 \r \n" ); document.write( "\n" ); document.write( "the father is 42 now and the son is 21 now \n" ); document.write( "when the father is 52 the son will be 31 \n" ); document.write( " \n" ); document.write( " |