document.write( "Question 849807: Ana has one coin of 5 cents, one coin of 10 cents, one coin of 20 cents and one coin of 50 cents. How many possible values she can make from these coins. \n" ); document.write( "
Algebra.Com's Answer #511807 by Edwin McCravy(20060)\"\" \"About 
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document.write( "No 1 2,3,4, or 5 of those coins add up to the same value\r\n" );
document.write( "as any other 1,2,3,4, or 5, so every combination of coins\r\n" );
document.write( "gives a different value.\r\n" );
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document.write( "There are two choices we can make for each coin.\r\n" );
document.write( "They are:\r\n" );
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document.write( "1. Use it to form a value.\r\n" );
document.write( "2. Do not use it to form a value.\r\n" );
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document.write( "There are 2 choices to make for the 5 cent coin. (Use it or don't).\r\n" );
document.write( "There are 2 choices to make for the 10 cent coin.\r\n" );
document.write( "There are 2 choices to make for the 20 cent coin.\r\n" );
document.write( "There are 2 choices to make for the 50 cent coin.\r\n" );
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document.write( "Therefore there are 2×2×2×2 = 24 = 16 different values.\r\n" );
document.write( "However that includes the value 0, in which case we do not use any \r\n" );
document.write( "coins.  So we exclude the value 0 from the 16:\r\n" );
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document.write( "Answer = 15 values (not counting 0 cents).\r\n" );
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document.write( "These values are every multiple of 5 cents from 5 cents through 85\r\n" );
document.write( "cents, EXCEPT there is no way to have 40 cents or 45 cents.\r\n" );
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document.write( "Edwin
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