document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=849875>Question 849875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't understand what to do with the extra 192, please help! 1162$ dollars were raised, it costs 4 dollars per child ticket and 7 dollars per adult ticket, there were 192 people attending. I thought you would do 3x+4y=1162, but I am confused on whether or not to distribute the 192. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511792 by </B><A HREF=/tutors/aboutme.mpl?userid=Phillips54><B>Phillips54(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Phillips54><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Phillips54><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> then you would do:<BR>\n" );
document.write( "x+y=192<BR>\n" );
document.write( "so it would look like this:<BR>\n" );
document.write( "3x+4y=1162<BR>\n" );
document.write( " x+ y=192<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );