document.write( "Question 849813: a father is 25 years older than his son. The sum of their ages is 53 years. Find their ages
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Algebra.Com's Answer #511766 by Ash14(5)![]() ![]() ![]() You can put this solution on YOUR website! let age of father=x \n" ); document.write( "and age of his son =y \n" ); document.write( "now \n" ); document.write( "father is 25 years older than his son. \n" ); document.write( "means that \n" ); document.write( "x-y=25........(1)\r \n" ); document.write( "\n" ); document.write( "and \n" ); document.write( "the sum of their ages is 53 years \n" ); document.write( "means \n" ); document.write( "x+y=53.......(2)\r \n" ); document.write( "\n" ); document.write( "now from (1) and (2) \n" ); document.write( "x+y=53 \n" ); document.write( "x-y=25 \n" ); document.write( "============ (cancel y because y-y=0 and x+x=2x) \n" ); document.write( "2x=78 \n" ); document.write( "x=78/2 \n" ); document.write( "x=39\r \n" ); document.write( "\n" ); document.write( "sub value of x in (1) \n" ); document.write( "x-y=25 \n" ); document.write( "(39)-y=25(here we need to make y the subject) \n" ); document.write( "| \n" ); document.write( "| \n" ); document.write( "39=25+y \n" ); document.write( "39-25=y \n" ); document.write( "14=y\r \n" ); document.write( "\n" ); document.write( "so \n" ); document.write( "x=39(age of father) and y=14(age of son) \n" ); document.write( "....... \n" ); document.write( "******* \n" ); document.write( ".......\r \n" ); document.write( "\n" ); document.write( "good luck :)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |