document.write( "Question 71419: Someone please help!\r
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document.write( "One angle of a triangle exceeds another by 23 degrees. The third is 6 degrees less than the sum of the others. Find the measure of the angles.\r
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document.write( "I would really appreciate it if someone could help with this problem!
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document.write( "thanks! \n" );
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Algebra.Com's Answer #51172 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=one of the angles \n" ); document.write( "(x+23)=the other angle \n" ); document.write( "(x+(x+23)-6)=the third angle\r \n" ); document.write( "\n" ); document.write( "Now since this is a triangle, all three angles must add up to 180 degrees. So our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "x+(x+23)+(x+(x+23)-6)=180 get rid of parens\r \n" ); document.write( "\n" ); document.write( "x+x+23+x+x+23-6=180 collect like terms \n" ); document.write( "4x+40=180 subtract 40 from both sides \n" ); document.write( "4x+40-40=180-40 collect like terms again \n" ); document.write( "4x=140 divide both sides by 4 \n" ); document.write( "x=35 degrees-------------------one of the angles \n" ); document.write( "(x+23)=35+23=58 degrees-------------the other angle \n" ); document.write( "(x+(x+23)-6)=35+35+23-6=87 degrees------the third angle\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "87+58+35=180 \n" ); document.write( "180=180 \n" ); document.write( "also \n" ); document.write( "35+23=58 \n" ); document.write( "58=58 \n" ); document.write( "and \n" ); document.write( "35+58-6=87 \n" ); document.write( "87=87\r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |