document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=849725>Question 849725</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In an arithmetic series, the terms of the series are equally spread out. For example, in<BR>\n" );
document.write( "1 + 5 + 9 + 13 + 17, consecutive terms are 4 apart. If the first term in an arithmetic series is<BR>\n" );
document.write( "3, the last term is 136, and the sum is 1,390, what are the first 3 terms? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511706 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sn = (A1 + An)/2 * n \r<BR>\n" );
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document.write( "1390 = (3+136)/2 * n\r<BR>\n" );
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document.write( "2780 = 139n\r<BR>\n" );
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document.write( "n = 20\r<BR>\n" );
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document.write( "136 = 3 + (20-1)*d\r<BR>\n" );
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document.write( "136 = 3 + 19d\r<BR>\n" );
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document.write( "133 = 19d\r<BR>\n" );
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document.write( "d = 7\r<BR>\n" );
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document.write( "3, 3+7, 3+2*7\r<BR>\n" );
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document.write( "3,10,17 </SPAN>\n" );
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