document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=9225>Question 9225</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this word problem. It deals with solving quadratic equations by finding square roots.\r<BR>\n" );
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document.write( "A baseball diamond is actually a square with sides of 90 feet. With Runners on 1st and 2nd, the third baseman fields a ball, runs to third base to get a force out and then throws the ball to first for a double play. Find the length of the third baseman's throw to the nearest foot. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5117 by </B><A HREF=/tutors/aboutme.mpl?userid=DWL><B>DWL(56)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DWL><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem is a trigonometry problem using triangles:\r<BR>\n" );
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document.write( "It involves the use of Pythagorean Theorem, which says: \"In algebraic <BR>\n" );
document.write( "terms, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2Bb%5E2=c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2Bb%5E2=c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where c is the hypotenuse while a and b are the <BR>\n" );
document.write( "sides of the triangle.\r<BR>\n" );
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document.write( "Think of the basball diamond as a square, and at each base a corner of <BR>\n" );
document.write( "the square with each corner being a 90 degree angle.  So if we draw a <BR>\n" );
document.write( "line from third base to first base we cut the square in half.\r<BR>\n" );
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document.write( "We now have two right triangles.\r<BR>\n" );
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document.write( "The first leg of the triangle is from first base to second base, the <BR>\n" );
document.write( "second leg of the triangle is from second base to third base and the <BR>\n" );
document.write( "distance from third base across the field to first base is the hypotenuse.\r<BR>\n" );
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document.write( "we can now solve this problem.\r<BR>\n" );
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document.write( "Distance from First to Second = 90 Ft., we will call this A\r<BR>\n" );
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document.write( "Distance from Second to Third = 90 Ft., We will call this B\r<BR>\n" );
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document.write( "Throwing distance from third to First = ?, We will call this C\r<BR>\n" );
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document.write( "So we know that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2%2BB%5E2=C%5E2 ALIGN=MIDDLE  ALT=\"A%5E2%2BB%5E2=C%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So we subsitute the numbers we know:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90%5E2%2B90%5E2=C%5E2 ALIGN=MIDDLE  ALT=\"90%5E2%2B90%5E2=C%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So squaring the numbers we get: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8100%2B8100=C%5E2 ALIGN=MIDDLE  ALT=\"8100%2B8100=C%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "We then take the square root of both sides to get\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%288100%2B8100%29=C%29 ALIGN=MIDDLE  ALT=\"sqrt%288100%2B8100%29=C%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2816200%29=C ALIGN=MIDDLE  ALT=\"sqrt%2816200%29=C\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "127.28 = C\r<BR>\n" );
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document.write( "So the answer to the nearest Ft. is 127 Feet.  Is how far the 3rd. Baseman threw the ball to the fist baseman </SPAN>\n" );
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