document.write( "Question 849645: A small business just leased a new computer and color laser printer for three years. The service
\n" ); document.write( "contract for the computer offers unlimited repairs for a fee of $100 a year plus a $25 service charge for
\n" ); document.write( "each repair needed. The company’s research suggested that during a given year 86% of these
\n" ); document.write( "computers needed no repairs, 9% needed to be repaired once, 4% twice, 1% three times, and none
\n" ); document.write( "required more than three repairs.\r
\n" ); document.write( "\n" ); document.write( "a) Find the expected number of repairs this computer needs each year\r
\n" ); document.write( "\n" ); document.write( "b.)The standard deviation of the number of repairs each year is 0.55. What is the standard deviation of
\n" ); document.write( "the company's annual expense for the service contract?
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Algebra.Com's Answer #511674 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
1) \"0%28.86%29+%2B+1%28.09%29+%2B+2%28.04%29+%2B+3%28.01%29+=+highlight%280.2%29\"\r
\n" ); document.write( "\n" ); document.write( "2) E[annual expense] = 100(.86) + 125(.09) + 150(.04) + 175(.01) = 105\r
\n" ); document.write( "\n" ); document.write( "E[(annual expense)^2] = 100^2(.86) +125^2(.09) + 150^2(.04) + 175^2(.01) = 11212.5\r
\n" ); document.write( "\n" ); document.write( "I'll short hand annual expense = A.\r
\n" ); document.write( "\n" ); document.write( "Var[A] = E[A^2] -[E[A]]^2\r
\n" ); document.write( "\n" ); document.write( "Var[A] = 11212.5 - 105^2 = 187.5\r
\n" ); document.write( "\n" ); document.write( "SD[A] = \"sqrt%28Var%28A%29%29+=+sqrt%28187.5%29+=+highlight%2813.69%29\"
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