document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=849516>Question 849516</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have two absolute question. The first is 3|6-d|=18 and the other one is <BR>\n" );
document.write( "1/4|6x-3|=18.75 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511609 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first problem:\r<BR>\n" );
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document.write( "3|6-d| = 18\r<BR>\n" );
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document.write( "divide both sides of this equation by 3 to get:\r<BR>\n" );
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document.write( "|6-d| = 6\r<BR>\n" );
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document.write( "break this up into 2 equations as follows:\r<BR>\n" );
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document.write( "first equation is (6-d) = 6\r<BR>\n" );
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document.write( "second equation is (6-d) = -6\r<BR>\n" );
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document.write( "first equation is solved as follows:\r<BR>\n" );
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document.write( "6-d = 6<BR>\n" );
document.write( "subtract 6 from both sides of this equation to get:\r<BR>\n" );
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document.write( "-d = 0\r<BR>\n" );
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document.write( "multiply both sides of this equation by -2 to get:\r<BR>\n" );
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document.write( "d = 0\r<BR>\n" );
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document.write( "second equation is solved as follows:\r<BR>\n" );
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document.write( "(6-d) = -6\r<BR>\n" );
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document.write( "subtract 6 from both sides of this equation to get:\r<BR>\n" );
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document.write( "-d = -12\r<BR>\n" );
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document.write( "multiply both sidesof this equation by -1 to get:\r<BR>\n" );
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document.write( "d = 12\r<BR>\n" );
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document.write( "your solutions are that d is either equal to 0 or d is equal to 12.\r<BR>\n" );
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document.write( "confirm by substituting in the original equation.\r<BR>\n" );
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document.write( "3 * |6-d| = 18 is the original equation.\r<BR>\n" );
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document.write( "replace d with 0 to get 3 * |6-0| = 18 which simplifies to:\r<BR>\n" );
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document.write( "18 = 18, confirming d = 0 is good.\r<BR>\n" );
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document.write( "replace d with 12 to get 3 * |6 - 12| = 18 which simplifies to:\r<BR>\n" );
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document.write( "3 * |-6| = 18 which becomse 18 = 18 because the absolute value of -6 is equal to 6.\r<BR>\n" );
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document.write( "both solutions are confirmed to be true.\r<BR>\n" );
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document.write( "second problem:\r<BR>\n" );
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document.write( "1/4 * |6x-3| = 18.75\r<BR>\n" );
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document.write( "multiply both sides of this equation by 4 and you get:\r<BR>\n" );
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document.write( "|6x-3| = 75\r<BR>\n" );
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document.write( "break this up into 2 equations:\r<BR>\n" );
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document.write( "first equation is (6x-3) = 75\r<BR>\n" );
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document.write( "second equation is (6x-3) = -75\r<BR>\n" );
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document.write( "solve each equation for x.\r<BR>\n" );
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document.write( "first equation is solved as follows:<BR>\n" );
document.write( "6x-3 = 75<BR>\n" );
document.write( "add 3 to both sides to get:<BR>\n" );
document.write( "6x = 78<BR>\n" );
document.write( "divide both sides by 6 to get:<BR>\n" );
document.write( "x = 13\r<BR>\n" );
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document.write( "second equation is solved as follows:<BR>\n" );
document.write( "6x-3 = -75<BR>\n" );
document.write( "add 3 to both sides to get:<BR>\n" );
document.write( "6x = -72<BR>\n" );
document.write( "divide both sides by 6 to get:<BR>\n" );
document.write( "x = -12\r<BR>\n" );
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document.write( "x is either 13 or -12\r<BR>\n" );
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document.write( "when x is 13, 1/4 * |6x-3| is equal to 1/4 * |75| which is equal to 18.75.\r<BR>\n" );
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document.write( "when x is -12, 1/4 * |6x-3| is equal to 1/4 * |-75| which is equal to 18.75.\r<BR>\n" );
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document.write( "this is because the absolute value of a number is always positive.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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