document.write( "Question 849490: Solve Algecraically:\r
\n" ); document.write( "\n" ); document.write( "\"5%2Fx%2B4+-+3%2Fx%2B2+=+4\"
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Algebra.Com's Answer #511600 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
You ask for how to solve this: \"5%2Fx%2B4+-+3%2Fx%2B2+=+4\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply left and right sides by x which clears the denominators.
\n" ); document.write( "\"5%2B4x-3%2B2x=4x\"
\n" ); document.write( "Now isolate the terms of x.
\n" ); document.write( "\"4x%2B2x-4x=-5%2B3\"
\n" ); document.write( "\"2x=-2\"
\n" ); document.write( "\"x=-1\"------DONE.
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