document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=849453>Question 849453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone show me how to write the partial fraction decomposition of (2x-3)/(x^2-2x+1) I don't know how to do this type of problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511594 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511594\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  partial fraction decomposition of (2x-3)/(x^2-2x+1)<BR>\n" );
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document.write( "DEN = (x-1)^2<BR>\n" );
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document.write( "(2x-3)/(x^2-2x+1) = A/(x-1)^2 + B/(x-1)<BR>\n" );
document.write( "(2x-3)/(x^2-2x+1) = A/(x-1)^2 + B(x-1)/(x-1)^2<BR>\n" );
document.write( "2x-3 = A + Bx - B<BR>\n" );
document.write( "2x = Bx<BR>\n" );
document.write( "B = 2<BR>\n" );
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document.write( "A - B = -3<BR>\n" );
document.write( "A = -1<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "(2x-3)/(x^2-2x+1) = -1/(x-1)^2 + 2/(x-1) ?<BR>\n" );
document.write( "(2x-3)/(x^2-2x+1) = -1/(x-1)^2 + 2*(x-1)/(x-1)^2 ?<BR>\n" );
document.write( "(2x-3) = -1 + 2*(x-1) ?<BR>\n" );
document.write( "2x-3 = 2x - 3 it's correct </SPAN>\n" );
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