document.write( "Question 71529: find three consecutive odd integers such that three times the second number added to twice the third number is seven times the first integer. find the three consecutive odd integers. \n" ); document.write( "

Algebra.Com's Answer #51159 by ptaylor(2198) $\"\"$ $\"About$

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Let x=first integer
\n" ); document.write( "Then x+2=second integer
\n" ); document.write( "And x+4=third integer\r
\n" ); document.write( "\n" ); document.write( "3(x+2)=three times the second number
\n" ); document.write( "2(x+4)=twice the third number\r
\n" ); document.write( "\n" ); document.write( "Now we are told that:
\n" ); document.write( "3(x+2)+2(x+4)=7x get rid of parens\r
\n" ); document.write( "\n" ); document.write( "3x+6+2x+8=7x collect like terms
\n" ); document.write( "5x+14=7x subtract 5x from both sides
\n" ); document.write( "14=7x-5x
\n" ); document.write( "14=2x divide both sides by 2
\n" ); document.write( "x=7------------------first integer
\n" ); document.write( "x+2=9----------------------second integer
\n" ); document.write( "x+4=11--------------------------3rd integer\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "3(9)+2(11)=7(7)
\n" ); document.write( "27+22=49
\n" ); document.write( "49=49\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor\r
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