document.write( "Question 71531This question is from textbook Pre-Algebra CA Edition
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document.write( ": A cell phone company charges $27.95 per month and 12 cents a min for local calls. Another cell phone company charges $12.95 a month and 32 cents a min for local calls. For what number of minutes of local calls is the cost of the plans same? \n" );
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Algebra.Com's Answer #51158 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let x= number of minutes of local calls when cost of plans are the same\r \n" ); document.write( "\n" ); document.write( "Cost of Plan 1=$27.95+.12x \n" ); document.write( "Cost of Plan 2=$12.95+.32x\r \n" ); document.write( "\n" ); document.write( "Need to find x when Cost of Plan 1=Cost of Plan 2. So, our equation to solve:\r \n" ); document.write( "\n" ); document.write( "$27.95+.12x=$12.95+.32x subtract $12.95 and.12x from both sides\r \n" ); document.write( "\n" ); document.write( "$27.95-$12.95+.12x-.12x=$12.95-$12.95+.32x-.12x collect like terms\r \n" ); document.write( "\n" ); document.write( "$15.00=.20x divide both sides by .20\r \n" ); document.write( "\n" ); document.write( "x=75 minutes------------------------------when costs are the same\r \n" ); document.write( "\n" ); document.write( "ck\r \n" ); document.write( "\n" ); document.write( "27.95+.12(75)=12.95+.32(75) \n" ); document.write( "27.95+9.00=12.95+24.00\r \n" ); document.write( "\n" ); document.write( "36.95=36.95\r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |