document.write( "Question 71534: the length of a rectangular playing field is 5ft less than twice its width. If the perimeter of the playing field is 230ft, find the length and width on the field. \n" ); document.write( "
Algebra.Com's Answer #51157 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=width (w) \n" ); document.write( "Then 2x-5=length(l)\r \n" ); document.write( "\n" ); document.write( "Perimeter=230=2w+2l So, our equation to solve:\r \n" ); document.write( "\n" ); document.write( "2x+2(2x-5)=230 get rid of parens\r \n" ); document.write( "\n" ); document.write( "2x+4x-10=230 add 10 to both sides\r \n" ); document.write( "\n" ); document.write( "2x+4x-10+10=230+10 collect like terms\r \n" ); document.write( "\n" ); document.write( "6x=240 divide both sides by 6\r \n" ); document.write( "\n" ); document.write( "x=40 ft--------------width\r \n" ); document.write( "\n" ); document.write( "2x-5=80-5=75 ft ------------length\r \n" ); document.write( "\n" ); document.write( "ck\r \n" ); document.write( "\n" ); document.write( "2(75)+2(40)=230 \n" ); document.write( "150+80=230 \n" ); document.write( "230=230\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " \n" ); document.write( " |