document.write( "Question 848888: Please help I've tried so many times! \r
\n" ); document.write( "\n" ); document.write( "The energy E(x) of an electron after passing through material of thickness x is given by the equation
\n" ); document.write( "E(x) = E (base 0) e^(-x/x0) where E0 is the initial energy and x0 is the radiation wavelength.\r
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\n" ); document.write( "\n" ); document.write( "(a) Express, in terms of E0, the energy of an electron after it passes through material of thickness x0.
\n" ); document.write( "E(x0) =\r
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\n" ); document.write( "\n" ); document.write( "(b) Express, in terms of x0, the thickness at which the electron loses 91% of its initial energy. (Round your coefficient to two decimal places.)
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Algebra.Com's Answer #511560 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "E(x) = E[0]e^(-x/x0)
\n" ); document.write( "E(x0) = E[0]e^(-x0/x0)
\n" ); document.write( "E(x0) = E[0]e^(-1)\r
\n" ); document.write( "\n" ); document.write( "loses 91% of its initial energy ( 9% remains)
\n" ); document.write( "E(x) = E[0]e^(-x/x0)
\n" ); document.write( "E(x)\E[0] =e^(-x/x0)
\n" ); document.write( ".09 =e^(-x/x0)
\n" ); document.write( "ln(.09)= -x/x0
\n" ); document.write( "(-x0)ln(.09) = x\r
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