document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=849464>Question 849464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cereal maker places a game piece in each of it's cereAl boxes. The probablility of winning a prize is 1 in 4. Find the probablility that you a.) win your first prize on your fourth purchase. B.) win your prize with your first, second, or third purchase and c.) do not win a prize with your first four purchases. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511554 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511554\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A cereal maker places a game piece in each of it's cereAl boxes. The probablility of winning a prize is 1 in 4. Find the probablility that you <BR>\n" );
document.write( "a.) win your first prize on your fourth purchase.:::(3/4)^3(1/4) = 27/256<BR>\n" );
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document.write( "B.) win your prize with your first, second, or third purchase <BR>\n" );
document.write( "(1/4) + (3/4)(1/4) + (3/4)^2(1/4) = (16 + 12 + 9)/64 = 37/64<BR>\n" );
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document.write( "c.) do not win a prize with your first four purchases.:: (3/4)^4 = 81/256 <BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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