document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=849430>Question 849430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In right triangle ABC with C =90°. If a=2.75ft , c=4.05ft,  solve for all the missing parts </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511537 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In right triangle ABC with C =90°. If a=2.75ft , c=4.05ft, solve for all the missing parts<BR>\n" );
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document.write( "Draw the picture: a is opposite A ; b is opposite B ; c is opposite C<BR>\n" );
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document.write( "sin(A) = a/c = 2.75/4.05<BR>\n" );
document.write( "A = arcsin(2.75/4.05) = 42.77 degrees<BR>\n" );
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document.write( "B = C - 42.77 = 47.23 degrees<BR>\n" );
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document.write( "b = 4.05*cos(47.23) = 2.75<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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