document.write( "Question 849368: how many distinct permutations can be made from the letters of the word \"mathematics\". \n" ); document.write( "
Algebra.Com's Answer #511534 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the word mathematics has:\r
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\n" ); document.write( "\n" ); document.write( "11 letters in total
\n" ); document.write( "2 of the letter 'a'
\n" ); document.write( "2 of the letter 'm'
\n" ); document.write( "2 of the letter 't'\r
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\n" ); document.write( "\n" ); document.write( "i believe that's all the duplicates.\r
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\n" ); document.write( "\n" ); document.write( "the permutation formula is 11! / (2! * 2! * 2!)\r
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\n" ); document.write( "\n" ); document.write( "this becomes 11! / 8 which is equal to 4,989,600.\r
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\n" ); document.write( "\n" ); document.write( "you take the permutation of the whole number and you divide by the permutation of each of the duplicates.\r
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\n" ); document.write( "\n" ); document.write( "for example:\r
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\n" ); document.write( "\n" ); document.write( "consider the letters ABC.\r
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\n" ); document.write( "\n" ); document.write( "the permutation of these is 3! = 6.\r
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\n" ); document.write( "\n" ); document.write( "those permutations are:\r
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\n" ); document.write( "\n" ); document.write( "ABC
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\n" ); document.write( "BAC
\n" ); document.write( "BCA
\n" ); document.write( "CAB
\n" ); document.write( "CBA\r
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\n" ); document.write( "\n" ); document.write( "now consider the permutation of the letters AAC.\r
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\n" ); document.write( "\n" ); document.write( "use the formula given above and you get 3! / 2! which is equal to 6/2 = 3.\r
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\n" ); document.write( "\n" ); document.write( "those permutations are:\r
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\n" ); document.write( "\n" ); document.write( "AAC
\n" ); document.write( "ACA
\n" ); document.write( "CAA\r
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