document.write( "Question 849259: a freight train leaves the train station 1 hour before a passenger train. The two trains are traveling in the same direction on parallel tracks. if the rate of the passenger train is 5 mph than the freight train, how fast is each train traveling if the passenger train passes the freight train in 12 hours? \n" ); document.write( "

Algebra.Com's Answer #511529 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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a freight train leaves the train station 1 hour before a passenger train.
\n" ); document.write( " The two trains are traveling in the same direction on parallel tracks.
\n" ); document.write( " if the rate of the passenger train is 5 mph more than the freight train,
\n" ); document.write( " how fast is each train traveling if the passenger train passes the freight train in 12 hours?
\n" ); document.write( ":
\n" ); document.write( "When the pass train catches the freight, they will have traveled the same dist.
\n" ); document.write( "From the information given we know the travel time of the pass is 12 hrs and the travel time of the freight is 13 hrs
\n" ); document.write( ":
\n" ); document.write( "let s = the speed of the freight
\n" ); document.write( "then
\n" ); document.write( "(s+5) = speed of the pass train
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation: dist = speed * time
\n" ); document.write( "13s = 12(s+5)
\n" ); document.write( "13s = 12s + 60
\n" ); document.write( "13s - 12 = 60
\n" ); document.write( "s = 60 mph is the speed of the freight
\n" ); document.write( "You can find the speed of the pass
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Pretty easy, right?
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "YOu can confirm this by finding the actual dist each train went, should be the same. \n" ); document.write( "

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