document.write( "Question 849303: a camp had enough food to last 50 days for 2200 soldiers . after 17 days some more soldiers joined the camp and the food remaining lasts for 20 days find the number of soldiers who joined later
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Algebra.Com's Answer #511509 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a camp had enough food to last 50 days for 2200 soldiers. \n" ); document.write( "50 * 2200 = 110000 man-food days available \n" ); document.write( ": \n" ); document.write( "After 17 days some more soldiers joined the camp and the food remaining lasts for 20 days \n" ); document.write( " Find the number of soldiers who joined later \n" ); document.write( " Let x = no. of soldiers who joined later \n" ); document.write( ": \n" ); document.write( "17(2200) + 20(x+2200) = 110000 \n" ); document.write( "37400 + 20x + 44000 = 110000 \n" ); document.write( "20x + 81400 = 110000 \n" ); document.write( "20x = 110000 - 81400 \n" ); document.write( "20x = 28600 \n" ); document.write( "x = 28600/20 \n" ); document.write( "x = 1430 men joined after 17 days\r \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |