document.write( "Question 9352: Have several problems like this one: (Need a formula) \r
\n" ); document.write( "\n" ); document.write( "Mr. Merrill has 3 times as many nickels as dimes. The coins have a total value of $1.50. How many of each coin does he have? (I know the answer is 18 nickels and 6 dimes but it comes from experience of handling change in a store and I don't know how to arrive at a formula or equation.)
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Algebra.Com's Answer #5115 by DWL(56)\"\" \"About 
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Let X = dimes\r
\n" ); document.write( "\n" ); document.write( "Let Y = Nickels\r
\n" ); document.write( "\n" ); document.write( "We know Y = 3X\r
\n" ); document.write( "\n" ); document.write( "We also know that .10 = Dimes and .05 = Nickles\r
\n" ); document.write( "\n" ); document.write( "So X+Y=1.50\r
\n" ); document.write( "\n" ); document.write( "We substitue the following:\r
\n" ); document.write( "\n" ); document.write( ".10X + 3(.05X)=1.50\r
\n" ); document.write( "\n" ); document.write( ".10X + .15X = 1.50\r
\n" ); document.write( "\n" ); document.write( ".25X = 1.50\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by .25\r
\n" ); document.write( "\n" ); document.write( "X = 6 Dimes\r
\n" ); document.write( "\n" ); document.write( "So we know we have 3 times as many nickels as dimes, 6 x 3 = 18.\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "6 dimes = .60
\n" ); document.write( "18 Nickels = .90\r
\n" ); document.write( "\n" ); document.write( "Total = 1.50
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