document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=849317>Question 849317</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the ratio of lengths on a model car to the lengths on the actual car is 1.15.A tyre on the model car is 3cm in diameter. what is the diameter  of the actual tyre<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511473 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Notation is important.  Do you want to express the ratio as 1.15, or as 1:15?  These are unequal.  The ratio is as, Model:Actual, ratio of model length to actual length.  This is judged to be the 1:15 based on the small size of 3 CENTIMETERS for the model's diameter.\r<BR>\n" );
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document.write( "You want this proportion:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2Fu=1%2F15 ALIGN=MIDDLE  ALT=\"3%2Fu=1%2F15\"   DISABLED_style= \"max-width:90%; height:auto;\" >  using u as the actual diameter of the wheel in cm, and is unknown but solvable. </SPAN>\n" );
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