document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=849269>Question 849269</A>: <I><SPAN STYLE=\"word-break: break-all;\"> SOLUTION: Write a power Function of the form y=ab^x whose graph passes through the given points: (2,4) (3,7)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511461 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511461\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This may be a misunderstanding for the way in which you want the solution; but take logarithms of both sides:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%28y%29%29=log%28%28ab%5Ex%29%29 ALIGN=MIDDLE  ALT=\"log%28%28y%29%29=log%28%28ab%5Ex%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%28y%29%29=log%28%28a%29%29%2Bx%2Alog%28%28b%29%29 ALIGN=MIDDLE  ALT=\"log%28%28y%29%29=log%28%28a%29%29%2Bx%2Alog%28%28b%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%28y%29%29=x%2Alog%28%28b%29%29%2Blog%28%28a%29%29 ALIGN=MIDDLE  ALT=\"log%28%28y%29%29=x%2Alog%28%28b%29%29%2Blog%28%28a%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Next, choose the base you want for those logarithms, either e or 10, or whatever you best want; and use the points given, to make two linear equations.\r<BR>\n" );
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document.write( "SYSTEM:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%284%29%29=2%2Alog%28%28b%29%29%2Blog%28%28a%29%29 ALIGN=MIDDLE  ALT=\"log%28%284%29%29=2%2Alog%28%28b%29%29%2Blog%28%28a%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%287%29%29=3%2Alog%28%28b%29%29%2Blog%28%28a%29%29 ALIGN=MIDDLE  ALT=\"log%28%287%29%29=3%2Alog%28%28b%29%29%2Blog%28%28a%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Solving this system first eliminating log(a), you find <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%28b%29%29=log%28%287%29%29-log%28%284%29%29 ALIGN=MIDDLE  ALT=\"log%28%28b%29%29=log%28%287%29%29-log%28%284%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Continuing using substitution you find <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%28a%29%29=log%28%287%29%29%2B3%2Alog%28%284%29%29-3%2Alog%28%287%29%29 ALIGN=MIDDLE  ALT=\"log%28%28a%29%29=log%28%287%29%29%2B3%2Alog%28%284%29%29-3%2Alog%28%287%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Like I said, you need to choose a base for these logarithms, and get values for log(b) and log(a), and then find antilogs of them.  \r<BR>\n" );
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document.write( "Base 10 logarithms gives these:<BR>\n" );
document.write( "log(b)=0.243038, b=1.75.<BR>\n" );
document.write( "log(a)=0.12422, a=1.3311<BR>\n" );
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document.write( "Equation: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28highlight%28y=%281.3311%29%281.75%29%5Ex%29%29 ALIGN=MIDDLE  ALT=\"highlight%28highlight%28y=%281.3311%29%281.75%29%5Ex%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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