document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=849154>Question 849154</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if six sided dice are rolled what Is the probability of getting a sum of 5 or 11? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511402 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming 2 of these dice are rolled. Make a table like you see below\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" width = \"300\" src = \"http://bestcase.files.wordpress.com/2011/01/dicediagram.jpg\">\r<BR>\n" );
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document.write( "(Image Source: <a  rel=nofollow HREF=\"http://bestcase.wordpress.com/2011/01/08/an-empirical-approach-to-dice-probability/\">http://bestcase.wordpress.com/2011/01/08/an-empirical-approach-to-dice-probability/</a>)\r<BR>\n" );
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document.write( "Note: each cell is found by adding the row and column header. For instance, the '8' in row 3, column 5 is found by adding 3 and 5. So 3+5 = 8. The other cells are found this way.\r<BR>\n" );
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document.write( "You can see that there are 4 copies of '5' and 2 copies of '11'. So there are 4+2 = 6 copies of what we want (which is either 5 or 11). \r<BR>\n" );
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document.write( "This is out of 6*6 = 36 possible outcomes. \r<BR>\n" );
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document.write( "So the answer as a fraction is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2F36+=+1%2F6 ALIGN=MIDDLE  ALT=\"6%2F36+=+1%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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