document.write( "Question 71498: 6x^+12x-12=0
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Algebra.Com's Answer #51134 by checkley75(3666)\"\" \"About 
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6X^2+12X-12=0 DIVIDE ALL TERMS BY 6
\n" ); document.write( "X^2+2X-2=0 NOW SOLVE USING THE QUADRATIC EQUATION
\n" ); document.write( "X=(-B+-SQRT[B^2-4AC])/2A
\n" ); document.write( "X=(-2+-SQRT[4-4*1*-2])/2*1
\n" ); document.write( "X=(-2+-SQRT[4+8]/2
\n" ); document.write( "X=(-2+-SQRT12)/2
\n" ); document.write( "X=(-2+-3.464)/2
\n" ); document.write( "X=(-2+3.464)/2
\n" ); document.write( "X=1.464/2
\n" ); document.write( "X=.732 ANSWER
\n" ); document.write( "X=(-2-3.464)/2
\n" ); document.write( "X=-5.464/2
\n" ); document.write( "X=-2.732 ANSWER\r
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