document.write( "Question 848999: Please how to calculate the cubic root of numbers by hand.Please help me with this equation\r
\n" ); document.write( "\n" ); document.write( "35=3*(8.5) + (cubic root a + (169))\r
\n" ); document.write( "\n" ); document.write( "Please give me a detailed explanation and solution to this question.
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Algebra.Com's Answer #511337 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
You are trying to show \"35=3%2A%288.5%29%2B%28root%283%2Ca%29%2B169%29\" according to what you wrote.\r
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\n" ); document.write( "\n" ); document.write( "First, isolate the root(3,a).
\n" ); document.write( "\"35=3%288.5%29%2Broot%283%2Ca%29%2B169\"
\n" ); document.write( "\"root%283%2Ca%29=35-3%288.5%29-169\", the parentheses not having any effect.
\n" ); document.write( "\"root%283%2Ca%29=-159.5\"
\n" ); document.write( "This is the same as \"-root%283%2Ca%29=159.5\"; and the result would be irrational. \r
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\n" ); document.write( "\n" ); document.write( "There are methods to do this by hand; or you could do it in in a more simple manner using or starting from known cubes of whole numbers. You could go a bit fancier and use logarithms. No matter how to go through, the result will be an approximation.\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E3=125\"; \"6%5E3=216\"; you would or could test values between 5 and 6, being something near to 5.5.
\n" ); document.write( "(You would find that \"5.50%5E3=166.375\", and \"5.4%5E3=157.464\"; you might then either try linear interpolation, or look for another cubic multiplication between 5.4 and 5.5.)
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