document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=848897>Question 848897</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Stan paints twice as fast as Daniel. Working together, Stan and Daniel can paint 2,400 square feet in 4 hours. Another employee, Roger, joined their painting and together, Stan, Daniel & Sue can paint 3,600 square feet in 3 hours. \r<BR>\n" );
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document.write( "If Roger works alone, how many square feet can he paint in 4 hours and 27 minutes? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511322 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> s=2d<BR>\n" );
document.write( "s+d=3d<BR>\n" );
document.write( "3d=2400 in 4 hours<BR>\n" );
document.write( "d=800 in 4 hrs 200 in 1 hr<BR>\n" );
document.write( "s=1600 in 4 hrs 400 in one hour\r<BR>\n" );
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document.write( "3*200+3*400=600+1200=1800 for s and d in 3 hours<BR>\n" );
document.write( "which means that Roger and Sue can  do 1800 sq ft in 3 hours.<BR>\n" );
document.write( "We don't have enough info to know how Roger works alone.\r<BR>\n" );
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document.write( "If you meant roger and sue alone then ask again.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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