document.write( "Question 848887: Please solve I'm so lost! \r
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document.write( "Log (base 2) x+3=log (base 2) x-3 + log (base 6) 36 +3 \n" );
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Algebra.Com's Answer #511308 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Log (base 2) x+3=log (base 2) x-3 + log (base 6) 36 +3 \n" ); document.write( "============================ \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x+3 = 32*(x-3) = 32x - 96 \n" ); document.write( "31x = 99 \n" ); document.write( "x = 99/31 \n" ); document.write( " |