document.write( "Question 848951: For the experiment of rolling an ordinary pair of dice, find the probability that the sum will be each of the following:\r
\n" );
document.write( "\n" );
document.write( "16. The first die is 2 or the sum is 6 or 7.\r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "17. The sum is 11 or the second die is 5.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #511302 by swincher4391(1107)![]() ![]() You can put this solution on YOUR website! Sum table \n" ); document.write( "2 3 4 5 6 7 \n" ); document.write( "3 4 5 6 7 8 \n" ); document.write( "4 5 6 7 8 9 \n" ); document.write( "5 6 7 8 9 10 \n" ); document.write( "6 7 8 9 10 11 \n" ); document.write( "7 8 9 10 11 12\r \n" ); document.write( "\n" ); document.write( "16)\r \n" ); document.write( "\n" ); document.write( "P[die is 2 or sum is 6 or 7] = P[1st die is 2] + p[sum is 6 or 7] - p[2 and sum is 6 or 7]\r \n" ); document.write( "\n" ); document.write( "(2,4) (2,5) satisfy both conditions so P[first is 2 and sum is 6 or 7] = 2/36 \r \n" ); document.write( "\n" ); document.write( "P[sum is 6 or 7] = 13/36\r \n" ); document.write( "\n" ); document.write( "1/6 + 13/36 - 2/36 = \n" ); document.write( "\n" ); document.write( "17)\r \n" ); document.write( "\n" ); document.write( "P[sum is 11] = 2/36 \n" ); document.write( "P[2nd die is 5] = 1/6 \n" ); document.write( "P[sum is 11 and 2nd die is 5] = 1/36 (5,6)\r \n" ); document.write( "\n" ); document.write( "2/36 + 1/6 - 1/36 = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |