document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=848691>Question 848691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of two numbers is 52. The sum of the same two numbers is 10. Find the sum of the reciprocals of the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511240 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x*y = 52\r<BR>\n" );
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document.write( "x+y = 10\r<BR>\n" );
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document.write( "x = 10 - y\r<BR>\n" );
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document.write( "(10-y) * y = 52\r<BR>\n" );
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document.write( "10y - y^2 = 52\r<BR>\n" );
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document.write( "y^2 - 10y + 52 = 0   Not possible.\r<BR>\n" );
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document.write( "We check the discriminant:\r<BR>\n" );
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document.write( "b^2 - 4ac =   100 -4*52 = -8 < 0.\r<BR>\n" );
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