document.write( "Question 71482: Hello, \r
\n" ); document.write( "\n" ); document.write( "Can someone please help me find the volume of a cone with a height of 4m and a diameter of 2.2m?\r
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\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #51124 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
The volume of a (right circular) cone is given by:
\n" ); document.write( "\"V+=+%281%2F3%29Ah\" where A = the area of the circular base and h = the height of the cone (4m).
\n" ); document.write( "Let's find the area of the circular base whose diameter, D, is 2.2m.
\n" ); document.write( "Using 3.14 as an approximation of \"%28pi%29\"
\n" ); document.write( "\"A+=+%28pi%29r%5E2\" But the radius, \"r+=+D%2F2\", so:
\n" ); document.write( "\"A+=+%28pi%29%28D%2F2%29%5E2\"
\n" ); document.write( "\"A+=+%283.14%29%282.2%2F2%29%5E2\"
\n" ); document.write( "\"A+=+%283.14%29%281.21%29\"
\n" ); document.write( "\"A+=+3.8\"sq. m.
\n" ); document.write( "Now you can calculate the volume using the initial formula \"V+=+%281%2F3%29Ah\"
\n" ); document.write( "\"V+=+%281%2F3%29%283.8%29%284%29\"
\n" ); document.write( "\"V+=+5.1\" Cu. m. Rounded to nearest tenth.
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