document.write( "Question 848618: #1) A batch of twelve batteries has two that are defective. Two are picked at random from the lot. What is the probability that at least one is defective? \n" ); document.write( "
Algebra.Com's Answer #511214 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "P(defective) 2/12 = 1/6 , P(not defective) = 5/6
\n" ); document.write( "Two picked
\n" ); document.write( "P(at least one defective) = 1 -P(none defective) = 1-(5/6)^2\r
\n" ); document.write( "\n" ); document.write( "Note: The probability of x successes in n trials is:
\n" ); document.write( "P = nCx* \"p%5Ex%2Aq%5E%28n-x%29\" where p and q are the probabilities of success and failure respectively.
\n" ); document.write( "In this case p = 1/6 & q = 5/6. n = 2
\n" ); document.write( "\"+nCx+=+%28n%21%29%2Fx%21%28n+-+x%29%21%29\" \r
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