document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71463>Question 71463</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0138334846/algebrahomeworkh>Prentice Hall Mathematics</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Question: -2 (y + 6) = y + 3 + 2y<BR>\n" );
document.write( "- 2y - 12 = 3y + 3<BR>\n" );
document.write( "+ 2y      + 2y<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "- 12 = 5y + 3<BR>\n" );
document.write( "- 3       - 3<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "- 9 = 5y   Do I divide 5 on each side from here?<BR>\n" );
document.write( "I got 1.8 = y ???<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51121 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51121\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for y:<BR>\n" );
document.write( "-2(y+6) = y+3+2y<BR>\n" );
document.write( "Your first steps were good...until you got to:<BR>\n" );
document.write( "-12 = 5y+3 Then you tried to subtract 3 but made a mistake.<BR>\n" );
document.write( "-12-3 = 5y+3-3<BR>\n" );
document.write( "-15 = 5y Divide both sides by 5.<BR>\n" );
document.write( "-3 = y<BR>\n" );
document.write( "So y = -3.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "-2(-3+6) = -3+3+2(-3)<BR>\n" );
document.write( "-2(3) = 2(-3)<BR>\n" );
document.write( "-6 = -6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );